## Detailed calculations below:

### Introduction. Fractions

#### A fraction consists of two numbers and a fraction bar: ^{300}/_{1,200}

#### The number above the bar is the numerator: 300

#### The number below the bar is the denominator: 1,200

#### The fraction bar means that the two numbers are dividing themselves:

^{300}/_{1,200} = 300 ÷ 1,200

#### Divide the numerator by the denominator to get fraction's value:

Value = 300 ÷ 1,200

### Introduction. Percent

#### 'Percent (%)' means 'out of one hundred':

#### p% = p 'out of one hundred',

#### p% = ^{p}/_{100} = p ÷ 100

### Note:

#### The fraction ^{100}/_{100} = 100 ÷ 100 = 100% = 1

#### Multiply a number by the fraction ^{100}/_{100},

... and its value doesn't change.

## To reduce a fraction, divide both its numerator and denominator by their greatest common factor, GCF.

#### To calculate the greatest common factor, we build the prime factorization of the two numbers.

### Integer numbers prime factorization:

#### Prime Factorization of a number: finding the prime numbers that multiply together to make that number.

#### 300 = 2^{2} × 3 × 5^{2};

300 is not a prime, is a composite number;

#### 1,200 = 2^{4} × 3 × 5^{2};

1,200 is not a prime, is a composite number;

** Positive integers that are only dividing by themselves and 1 are called prime numbers. A prime number has only two factors: 1 and itself. *

* A composite number is a positive integer that has at least one factor (divisor) other than 1 and itself.

### Calculate the greatest (highest) common factor (divisor), gcf, hcf, gcd:

#### Multiply all the common prime factors, by the lowest exponents (if any).

#### gcf, hcf, gcd (300; 1,200) = 2^{2} × 3 × 5^{2} = 300

## Rewrite the end result:

### As a decimal number:

^{1}/_{4} =

#### 1 ÷ 4 =

#### 0.25

### As a percentage:

#### 0.25 =

#### 0.25 × ^{100}/_{100} =

#### ^{25}/_{100} =

#### 25%

#### In other words:

#### 1) Calculate fraction's value.

#### 2) Multiply that number by 100.

#### 3) Add the percent sign % to it.

## Final answer

continued below...